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DOC: Correct subplot() doc - #7760
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| Creating a new subplot with a position which is entirely inside a | ||
| pre-existing axes will trigger the larger axes to be deleted:: | ||
| Creating a new subplot with axes that overlap pre-existing axes will | ||
| trigger the pre-existing axes to be deleted:: |
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Something like "Creating a subplot will delete any pre-existing subplot that overlaps with it." seems clearer (possibly add "(if any)" at the end).
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Good suggestion @anntzer |
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lgtm |
| Creating a new subplot with a position which is entirely inside a | ||
| pre-existing axes will trigger the larger axes to be deleted:: | ||
| Creating a subplot will delete any pre-existing subplot that overlaps |
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Thanks @petehuang |
NelleV
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Please hold off. I think that both the code and the documentation are incomprehensible.
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I challenge anyone reading the proposed modification of the docstring, without poring over the code, to explain what "fully overlaps" means. Before reading the code, I was imagining that it might mean "encloses", as the original form of the docstring implied. Based on the Bbox method code, however, it means that the interiors intersect--that is, the intersection of the two rectangles encloses a finite area. Hence the subplot code is deleting any pre-existing subplots that have a finite intersection with the new subplot. Coinciding edges are not enough, because then the intersection encloses no area. |
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Ok let me paraphrase to make sure I understand correctly: you're saying that it's not determined by axes lying over one another, but it's that the rectangles that the axes create intersect in some way? I just want to make sure we get this explanation and the docstring in plain english |
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The practical problem is coming from the adverb "fully". The "overlaps" part is fine. The subtle distinction is that a shared boundary does not count as an "overlap". You could change "that fully overlaps with it" to "that has a finite area of overlap with it". Or "that overlaps with it beyond sharing a boundary". |
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I knew what the function did (and I find this behavior extremely strange…). |
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Thank you! |
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Backported to |
Fixes #7393