I would like to draw a rectangle to represent the weekend on a plot whose x-axis is time. In an IPython Notebook:
%pylab inline
dt = datetime.datetime
dates = [
dt(2015, 1, 1),
dt(2015, 1, 2),
dt(2015, 1, 3),
dt(2015, 1, 4),
dt(2015, 1, 5),
]
data = [56.0, 53.2, 57.8, 59.1, 55.5]
gca().add_patch(Rectangle(
xy=(dt(2015, 1, 3), 50.0),
width=datetime.timedelta(days=2),
height=1.0,
))
plot(dates, data)
The big problem is that the above code dies with an exception.
AttributeError Traceback (most recent call last)
<ipython-input-13-b4545adc3ff2> in <module>()
12 xy=(dt(2015, 1, 3), 50.0),
13 width=datetime.timedelta(days=2),
---> 14 height=1.0,
15 ))
16 plot(dates, data)
...
/home/brhodes/.v/misc/lib/python2.7/site-packages/matplotlib/dates.pyc in _to_ordinalf(dt)
202 dt -= delta
203
--> 204 base = float(dt.toordinal())
205 if hasattr(dt, 'hour'):
206 base += (dt.hour / HOURS_PER_DAY + dt.minute / MINUTES_PER_DAY +
AttributeError: 'datetime.timedelta' object has no attribute 'toordinal'
The other problem is that my backup plan, of replacing the timedelta() with the floating-point value 2.0, destroys the date-ness of the x axis. It reverts to being a float that does not display as a date.
Why is a timedelta not a valid increment or offset with which I can express width along a datetime x-axis?
Thanks for any help you can provide!
I would like to draw a rectangle to represent the weekend on a plot whose x-axis is time. In an IPython Notebook:
The big problem is that the above code dies with an exception.
The other problem is that my backup plan, of replacing the
timedelta()with the floating-point value 2.0, destroys the date-ness of thexaxis. It reverts to being a float that does not display as a date.Why is a
timedeltanot a valid increment or offset with which I can express width along a datetime x-axis?Thanks for any help you can provide!