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lualgorithm
/
AlgorithmAndDataStructure
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AlgorithmAndDataStructure
/
SwordToOffer
/
Code
/
45.py
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39 lines (33 loc) · 1.65 KB
master
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AlgorithmAndDataStructure
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SwordToOffer
/
Code
/
45.py
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# -*- coding:utf-8 -*-
'''
扑克牌顺子
LL今天心情特别好,因为他去买了一副扑克牌,发现里面居然有2个大王,2个小王(一副牌原本是54张^_^)...他随机从中抽出了5张牌,想测测自己的手气,看看能不能抽到顺子,如果抽到的话,他决定去买体育彩票,嘿嘿!!“红心A,黑桃3,小王,大王,方片5”,“Oh My God!”不是顺子.....LL不高兴了,他想了想,决定大\小 王可以看成任何数字,并且A看作1,J为11,Q为12,K为13。上面的5张牌就可以变成“1,2,3,4,5”(大小王分别看作2和4),“So Lucky!”。LL决定去买体育彩票啦。 现在,要求你使用这幅牌模拟上面的过程,然后告诉我们LL的运气如何, 如果牌能组成顺子就输出true,否则就输出false。为了方便起见,你可以认为大小王是0。
'''
class
Solution
:
def
IsContinuous
(
self
,
numbers
):
# write code here
numbers
=
sorted
(
numbers
)
size
=
len
(
numbers
)
count
=
0
pre
=
0
if
size
==
0
:
return
False
for
i
in
range
(
size
):
if
numbers
[
i
]
==
0
:
count
+=
1
else
:
if
pre
==
0
:
pre
=
numbers
[
i
]
else
:
if
numbers
[
i
]
==
pre
:
return
False
if
numbers
[
i
]
-
pre
==
1
:
pre
+=
1
else
:
count
=
count
-
(
numbers
[
i
]
-
pre
-
1
)
pre
=
numbers
[
i
]
if
count
<
0
:
return
False
return
True
s
=
Solution
()
print
s
.
IsContinuous
([
1
,
0
,
0
,
1
,
0
])
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