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| 1 | +package com.eprogrammerz.examples.algorithm.trees; |
| 2 | + |
| 3 | +import org.junit.Test; |
| 4 | + |
| 5 | +import java.util.ArrayList; |
| 6 | +import java.util.List; |
| 7 | + |
| 8 | +import static org.junit.Assert.assertEquals; |
| 9 | + |
| 10 | +/** |
| 11 | + * Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number. |
| 12 | + * |
| 13 | + * An example is the root-to-leaf path 1->2->3 which represents the number 123. |
| 14 | + * |
| 15 | + * Find the total sum of all root-to-leaf numbers % 1003. |
| 16 | + * |
| 17 | + * Example : |
| 18 | + * |
| 19 | + * 1 |
| 20 | + * / \ |
| 21 | + * 2 3 |
| 22 | + * The root-to-leaf path 1->2 represents the number 12. |
| 23 | + * The root-to-leaf path 1->3 represents the number 13. |
| 24 | + * |
| 25 | + * Return the sum = (12 + 13) % 1003 = 25 % 1003 = 25 |
| 26 | + * |
| 27 | + */ |
| 28 | +public class SumRoot2Leaf { |
| 29 | + public int sumNumbers(TreeNode root) { |
| 30 | + List<Integer> sumToLeafs = new ArrayList<>(); |
| 31 | + findSumToLeaf(root, sumToLeafs, 0); |
| 32 | + return sumToLeafs.stream().mapToInt(i -> i).sum() % 1003; |
| 33 | + } |
| 34 | + |
| 35 | + private void findSumToLeaf(TreeNode node, List<Integer> sumToLeafs, int sum) { |
| 36 | + if (node == null) return; |
| 37 | + |
| 38 | + if (node.left == null && node.right == null) { |
| 39 | + sumToLeafs.add(sum * 10 + node.val); |
| 40 | + return; |
| 41 | + } |
| 42 | + findSumToLeaf(node.left, sumToLeafs, sum * 10 + node.val); |
| 43 | + findSumToLeaf(node.right, sumToLeafs, sum * 10 + node.val); |
| 44 | + } |
| 45 | + |
| 46 | + @Test |
| 47 | + public void testSumNumbers() { |
| 48 | + System.out.println(1938 % 1003); |
| 49 | + /** |
| 50 | + * 6 |
| 51 | + * / \ |
| 52 | + * 3 7 |
| 53 | + * / \ \ |
| 54 | + * 2 5 1 |
| 55 | + * \ |
| 56 | + * 1 |
| 57 | + */ |
| 58 | + TreeNode root = new TreeNode(6); |
| 59 | + root.left = new TreeNode(3); |
| 60 | + root.right = new TreeNode(7); |
| 61 | + |
| 62 | + root.right.right = new TreeNode(1); |
| 63 | + |
| 64 | + root.left.left = new TreeNode(2); |
| 65 | + root.left.right = new TreeNode(5); |
| 66 | + |
| 67 | + // ((632) + (635) + (671)) % 1003 |
| 68 | + // 1938 % 1003 |
| 69 | + // 935 |
| 70 | + assertEquals(935, sumNumbers(root)); |
| 71 | + |
| 72 | + // add right node to rightest node on last level |
| 73 | + root.right.right.right = new TreeNode(1); |
| 74 | + assertEquals(957, sumNumbers(root)); |
| 75 | + |
| 76 | + } |
| 77 | + |
| 78 | + @Test |
| 79 | + public void testSumNumbers1() { |
| 80 | + System.out.println(512 % 1003); |
| 81 | + /** |
| 82 | + * 5 |
| 83 | + * / |
| 84 | + * 1 |
| 85 | + * / |
| 86 | + * 2 |
| 87 | + * |
| 88 | + * |
| 89 | + */ |
| 90 | + TreeNode root = new TreeNode(5); |
| 91 | + root.left = new TreeNode(1); |
| 92 | + |
| 93 | + root.left.left = new TreeNode(2); |
| 94 | + // (512) % 1003 |
| 95 | + // 512 |
| 96 | + assertEquals(512, sumNumbers(root)); |
| 97 | + } |
| 98 | +} |
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