Makefile: remove unused @@PERLLIBDIR@@ substitution variable

jrn · gitster · commit 90df2173f24c · 2018-04-24T10:58:18.000+09:00
Junio noticed that this variable is not quoted correctly when it is
passed to sed.  As a shell-quoted string, it should be inside
single-quotes like $(perllibdir_relative_SQ), not outside them like
$INSTLIBDIR.

In fact, this substitution variable is not used.  Simplify by removing
it.

Reported-by: Junio C Hamano &lt;gitster@pobox.com&gt;
Signed-off-by: Jonathan Nieder &lt;jrnieder@gmail.com&gt;
Signed-off-by: Junio C Hamano &lt;gitster@pobox.com&gt;
diff --git a/Makefile b/Makefile
@@ -2109,7 +2109,6 @@ GIT-PERL-HEADER: $(PERL_HEADER_TEMPLATE) GIT-PERL-DEFINES Makefile
 	INSTLIBDIR="$$INSTLIBDIR$${INSTLIBDIR_EXTRA:+:$$INSTLIBDIR_EXTRA}" && \
 	sed -e 's=@@PATHSEP@@=$(pathsep)=g' \
 	    -e 's=@@INSTLIBDIR@@='$$INSTLIBDIR'=g' \
-	    -e 's=@@PERLLIBDIR@@='$(perllibdir_SQ)'=g' \
 	    -e 's=@@PERLLIBDIR_REL@@=$(perllibdir_relative_SQ)=g' \
 	    -e 's=@@GITEXECDIR_REL@@=$(gitexecdir_relative_SQ)=g' \
 	    -e 's=@@LOCALEDIR_REL@@=$(localedir_relative_SQ)=g' \
