Fix doc typo: Updated ..< instead of ... for range operations in doc common.md#1254
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hsutter merged 1 commit intohsutter:mainfrom Sep 24, 2024
Merged
Fix doc typo: Updated ..< instead of ... for range operations in doc common.md#1254hsutter merged 1 commit intohsutter:mainfrom
..< instead of ... for range operations in doc common.md#1254hsutter merged 1 commit intohsutter:mainfrom
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Signed-off-by: Jost Triller <tsoj.tsoj@gmx.de>
gregmarr
reviewed
Aug 23, 2024
| | `(` `)` | `#!cpp f( 1, 2, 3)` | `#!cpp f( 1, 2, 3)` | | ||
| | `[` `]` | `#!cpp vec[123]` | `#!cpp vec[123]` | | ||
| | `...` | `#!cpp v.begin()...v.end()` | `#!cpp std::ranges::subrange(v.begin(), v.end())` | | ||
| | `..<` | `#!cpp v.begin()..<v.end()` | `#!cpp std::ranges::subrange(v.begin(), v.end())` | |
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@hsutter Should these two range operators be in the binary operators table instead of the unary operators table? Should the ... pack expansion then be in this table, or is it okay as the note below?
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Good point, I'll look at that post-merge
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Note: The
(),[],..<, and..=operators are treated as postfix unary operators, though they can take additional arguments.
I can kinda see how () and [] as pairs are considered postfix since they apply their contents to the thing to the left. Can you explain how ..< and ..= are treated as postfix unary? I don't understand what that means.
Owner
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Thanks! |
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