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fix: use pd.concat() instead df.append() in to_dataframe() to avoid warning #1478

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Merged
JoanFM merged 2 commits into from
Apr 28, 2023
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fix: use pd.concat() instead df.append() in to_dataframe() to avoid warning #1478

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e68f1bd
fix: use pd.concat instead df.append to avoid warning
Apr 28, 2023
673307e
fix: pd dataframe from dict
Apr 28, 2023
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3 changes: 2 additions & 1 deletion docarray/array/doc_list/io.py
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Original file line number Diff line number Diff line change
Expand Up @@ -544,7 +544,8 @@ def to_dataframe(self) -> 'pd.DataFrame':

for doc in self:
doc_dict = _dict_to_access_paths(doc.dict())
df = df.append(doc_dict, ignore_index=True)
doc_dict = {k: [v] for k, v in doc_dict.items()}

@JoanFM JoanFM Apr 28, 2023

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why do u need to convert them to list?

@anna-charlotte anna-charlotte Apr 28, 2023

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pd.DataFrame.from_dict() expects a dict with the column names as keys, and the values have to be a list, therefore I wrap the value with a list

@anna-charlotte anna-charlotte Apr 28, 2023 •
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like this v[0] would correspond to the first row, v[1] to the second row and so on. In our case we only have v[0] since len(v) = 1

df = pd.concat([df, pd.DataFrame.from_dict(doc_dict)], ignore_index=True)

return df

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