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AllIndicesOfNumber.java
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69 lines (62 loc) · 1.94 KB
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package recursion1;
import java.util.Scanner;
/*Given an array of length N and an integer x, you need to find all the indexes where x is present in the input array. Save all the indexes in an array (in increasing order).
Do this recursively. Indexing in the array starts from 0.
Input Format :
Line 1 : An Integer N i.e. size of array
Line 2 : N integers which are elements of the array, separated by spaces
Line 3 : Integer x
Output Format :
indexes where x is present in the array (separated by space)
Constraints :
1 <= N <= 10^3
Sample Input :
5
9 8 10 8 8
8
Sample Output :
1 3 4*/
public class AllIndicesOfNumber {
private static int[] allIndices(int[] arr, int x, int startIndex) {
if (startIndex >= arr.length) {
int[] output = new int[0];
return output;
}
int smallOutput[] = allIndices(arr, x, startIndex + 1);
if (arr[startIndex] == x) {
int output[] = new int[smallOutput.length + 1];
output[0] = startIndex;
for (int i = 0; i < smallOutput.length; i++) {
output[i + 1] = smallOutput[i];
}
return output;
} else {
return smallOutput;
}
}
public static int[] allIndices(int[] arr, int x) {
return allIndices(arr, x, 0);
}
public static int[] takeInput() {
Scanner scan = new Scanner(System.in);
int size = scan.nextInt();
int[] arr = new int[size];
for (int i = 0; i < size; i++) {
arr[i] = scan.nextInt();
}
return arr;
}
public static void printArray(int[] arr) {
for (int j : arr) {
System.out.print(j + "\t");
}
System.out.println();
}
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
int[] arr = takeInput();
int x = scan.nextInt();
int[] output = allIndices(arr, x);
printArray(output);
}
}