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Mar 30, 2024
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new question added #4

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46 changes: 45 additions & 1 deletion README.md
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Expand Up @@ -4,7 +4,7 @@ description: "Prepare for your next 2024 JavaScript interview with these tricky
githubPath: "https://github.com/Vasu7389/JavaScript-Interview-Questions"
---

<span style=" font-size: 1rem; border-bottom: 1px solid grey;"> Updated Jan 07, 2024 </span>
<span style=" font-size: 1rem; border-bottom: 1px solid grey;"> Updated Mar 31, 2024 </span>

In this article, we will cover a range of JavaScript interview questions, including those related to the latest versions of the language (ES6, ES7, ES8, and ES9).

Expand Down Expand Up @@ -1551,3 +1551,47 @@ console.log(numbers.reduce((total, num) => total + num));
4. **Output:** The final `console.log()` statement outputs the result of the `reduce()` operation, which is 30 (the sum of all the doubled numbers in the array).

</details>

<details>
<summary>
<h3>47. Write a JavaScript function that takes an array of numbers as input and returns a new array containing only the even numbers.</h3>

_*You can't use built-in methods like filter or forEach._

</summary>

**Answer:**

Approach 1: Using a loop and conditional statement

```js
function findEvenNumbers(numberArray) {
const evenNumbers = [];
for (let i = 0; i < numberArray.length; i++) {
if (numberArray[i] % 2 === 0) {
evenNumbers.push(numberArray[i]);
}
}
return evenNumbers;
}
```

Approach 2: Using recursion and conditional statement

```js
function findEvenNumbersRecursive(numberArray) {
if (numberArray.length === 0) {
return [];
}

const firstNumber = numberArray[0];
const remainingNumbers = numberArray.slice(1);

if (firstNumber % 2 === 0) {
return [firstNumber].concat(findEvenNumbersRecursive(remainingNumbers));
} else {
return findEvenNumbersRecursive(remainingNumbers);
}
}
```
</details>