TheAlgorithms · raklaptudirm · Oct 6, 2021 · Oct 5, 2021 · Oct 6, 2021
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+/*
+  Problem: Given two numbers, n and k, make all unique combinations of k numbers from 1 to n and in sorted order
+
+  What is combinations?
+  - Combinations is selecting items froms a collections without considering order of selection
+
+  Example:
+  - We have an apple, a banana, and a jackfruit
+  - We have three objects, and need to choose two items, then combinations will be
+
+  1. Apple & Banana
+  2. Apple & Jackfruit
+  3. Banana & Jackfruit
+
+  To read more about combinations, you can visit the following link:
+  - https://betterexplained.com/articles/easy-permutations-and-combinations/
+
+  Solution:
+  - We will be using backtracking to solve this questions
+  - Take one element, and make all them combinations for k-1 elements
+  - Once we get all combinations of that element, pop it and do same for next element
+*/
+
+class Combinations {
+  constructor (n, k) {
+    this.n = n
+    this.k = k
+    this.combinationArray = [] // will be used for storing current combination
+  }
+
+  findCombinations (high = this.n, total = this.k, low = 1) {
+    if (total === 0) {
+      console.log(this.combinationArray)
+      return
+    }
+    for (let i = low; i <= high; i++) {
+      this.combinationArray.push(i)
+      this.findCombinations(high, total - 1, i + 1)
+      this.combinationArray.pop()
+    }
+  }
+}
+
+export { Combinations }
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+import { Combinations } from '../AllCombinationsOfSizeK'
+
+describe('AllCombinationsOfSizeK', () => {
+  it('should return 3x2 matrix solution for n = 3 and k = 2', () => {
+    const test1 = new Combinations(3, 2)
+    expect(test1.findCombinations).toEqual([[1, 2], [1, 3], [2, 3]])
+  })
+
+  it('should return 6x2 matrix solution for n = 3 and k = 2', () => {
+    const test2 = new Combinations(4, 2)
+    expect(test2.findCombinations).toEqual([[1, 2], [1, 3], [1, 4], [2, 3], [2, 4], [3, 4]])
+  })
+})