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Strings
=======
Strings are not like integers, floats, and booleans. A string is a
**sequence**, which means it is an ordered collection of other values.
In this chapter you’ll see how to access the characters that make up a
string, and you’ll learn about some of the methods strings provide.
A string is a sequence
----------------------
A string is a sequence of characters. You can access the characters one
at a time with the bracket operator:
::
>>> fruit = 'banana'
>>> letter = fruit[1]
The second statement selects character number 1 from fruit and assigns
it to letter.
The expression in brackets is called an **index**. The index indicates
which character in the sequence you want (hence the name).
But you might not get what you expect:
::
>>> letter
'a'
For most people, the first letter of ``'banana'`` is b, not a. But for
computer scientists, the index is an offset from the beginning of the
string, and the offset of the first letter is zero.
::
>>> letter = fruit[0]
>>> letter
'b'
So b is the 0th letter (“zero-eth”) of ``'banana'``, a is the 1th letter
(“one-eth”), and n is the 2th letter (“two-eth”).
As an index you can use an expression that contains variables and
operators:
::
>>> i = 1
>>> fruit[i]
'a'
>>> fruit[i+1]
'n'
But the value of the index has to be an integer. Otherwise you get:
::
>>> letter = fruit[1.5]
TypeError: string indices must be integers
len
---
len is a built-in function that returns the number of characters in a
string:
::
>>> fruit = 'banana'
>>> len(fruit)
6
To get the last letter of a string, you might be tempted to try
something like this:
::
>>> length = len(fruit)
>>> last = fruit[length]
IndexError: string index out of range
The reason for the IndexError is that there is no letter in ’banana’
with the index 6. Since we started counting at zero, the six letters are
numbered 0 to 5. To get the last character, you have to subtract 1 from
length:
::
>>> last = fruit[length-1]
>>> last
'a'
Or you can use negative indices, which count backward from the end of
the string. The expression fruit[-1] yields the last letter, fruit[-2]
yields the second to last, and so on.
Traversal with a for loop
-------------------------
A lot of computations involve processing a string one character at a
time. Often they start at the beginning, select each character in turn,
do something to it, and continue until the end. This pattern of
processing is called a **traversal**. One way to write a traversal is
with a while loop:
::
index = 0
while index < len(fruit):
letter = fruit[index]
print(letter)
index = index + 1
This loop traverses the string and displays each letter on a line by
itself. The loop condition is index < len(fruit), so when index is equal
to the length of the string, the condition is false, and the body of the
loop doesn’t run. The last character accessed is the one with the index
len(fruit)-1, which is the last character in the string.
As an exercise, write a function that takes a string as an argument and
displays the letters backward, one per line.
Another way to write a traversal is with a for loop:
::
for letter in fruit:
print(letter)
Each time through the loop, the next character in the string is assigned
to the variable letter. The loop continues until no characters are left.
The following example shows how to use concatenation (string addition)
and a for loop to generate an abecedarian series (that is, in
alphabetical order). In Robert McCloskey’s book *Make Way for
Ducklings*, the names of the ducklings are Jack, Kack, Lack, Mack, Nack,
Ouack, Pack, and Quack. This loop outputs these names in order:
::
prefixes = 'JKLMNOPQ'
suffix = 'ack'
for letter in prefixes:
print(letter + suffix)
The output is:
::
Jack
Kack
Lack
Mack
Nack
Oack
Pack
Qack
Of course, that’s not quite right because “Ouack” and “Quack” are
misspelled. As an exercise, modify the program to fix this error.
String slices
-------------
A segment of a string is called a **slice**. Selecting a slice is
similar to selecting a character:
::
>>> s = 'Monty Python'
>>> s[0:5]
'Monty'
>>> s[6:12]
'Python'
The operator returns the part of the string from the “n-eth” character
to the “m-eth” character, including the first but excluding the last.
This behavior is counterintuitive, but it might help to imagine the
indices pointing *between* the characters, as in Figure [fig.banana].
.. figure:: figs/banana.pdf
:alt: Slice indices.
Slice indices.
If you omit the first index (before the colon), the slice starts at the
beginning of the string. If you omit the second index, the slice goes to
the end of the string:
::
>>> fruit = 'banana'
>>> fruit[:3]
'ban'
>>> fruit[3:]
'ana'
If the first index is greater than or equal to the second the result is
an **empty string**, represented by two quotation marks:
::
>>> fruit = 'banana'
>>> fruit[3:3]
''
An empty string contains no characters and has length 0, but other than
that, it is the same as any other string.
Continuing this example, what do you think fruit[:] means? Try it and
see.
Strings are immutable
---------------------
It is tempting to use the operator on the left side of an assignment,
with the intention of changing a character in a string. For example:
::
>>> greeting = 'Hello, world!'
>>> greeting[0] = 'J'
TypeError: 'str' object does not support item assignment
The “object” in this case is the string and the “item” is the character
you tried to assign. For now, an object is the same thing as a value,
but we will refine that definition later (Section [equivalence]).
The reason for the error is that strings are **immutable**, which means
you can’t change an existing string. The best you can do is create a new
string that is a variation on the original:
::
>>> greeting = 'Hello, world!'
>>> new_greeting = 'J' + greeting[1:]
>>> new_greeting
'Jello, world!'
This example concatenates a new first letter onto a slice of greeting.
It has no effect on the original string.
Searching
---------
What does the following function do?
::
def find(word, letter):
index = 0
while index < len(word):
if word[index] == letter:
return index
index = index + 1
return -1
In a sense, find is the inverse of the operator. Instead of taking an
index and extracting the corresponding character, it takes a character
and finds the index where that character appears. If the character is
not found, the function returns -1.
This is the first example we have seen of a return statement inside a
loop. If word[index] == letter, the function breaks out of the loop and
returns immediately.
If the character doesn’t appear in the string, the program exits the
loop normally and returns -1.
This pattern of computation—traversing a sequence and returning when we
find what we are looking for—is called a **search**.
As an exercise, modify find so that it has a third parameter, the index
in word where it should start looking.
Looping and counting
--------------------
The following program counts the number of times the letter a appears in
a string:
::
word = 'banana'
count = 0
for letter in word:
if letter == 'a':
count = count + 1
print(count)
This program demonstrates another pattern of computation called a
**counter**. The variable count is initialized to 0 and then incremented
each time an a is found. When the loop exits, count contains the
result—the total number of a’s.
As an exercise, encapsulate this code in a function named count, and
generalize it so that it accepts the string and the letter as arguments.
Then rewrite the function so that instead of traversing the string, it
uses the three-parameter version of find from the previous section.
String methods
--------------
Strings provide methods that perform a variety of useful operations. A
method is similar to a function—it takes arguments and returns a
value—but the syntax is different. For example, the method upper takes a
string and returns a new string with all uppercase letters.
Instead of the function syntax upper(word), it uses the method syntax
word.upper().
::
>>> word = 'banana'
>>> new_word = word.upper()
>>> new_word
'BANANA'
This form of dot notation specifies the name of the method, upper, and
the name of the string to apply the method to, word. The empty
parentheses indicate that this method takes no arguments.
A method call is called an **invocation**; in this case, we would say
that we are invoking upper on word.
As it turns out, there is a string method named find that is remarkably
similar to the function we wrote:
::
>>> word = 'banana'
>>> index = word.find('a')
>>> index
1
In this example, we invoke find on word and pass the letter we are
looking for as a parameter.
Actually, the find method is more general than our function; it can find
substrings, not just characters:
::
>>> word.find('na')
2
By default, find starts at the beginning of the string, but it can take
a second argument, the index where it should start:
::
>>> word.find('na', 3)
4
This is an example of an **optional argument**; find can also take a
third argument, the index where it should stop:
::
>>> name = 'bob'
>>> name.find('b', 1, 2)
-1
This search fails because b does not appear in the index range from 1 to
2, not including 2. Searching up to, but not including, the second index
makes find consistent with the slice operator.
The in operator
---------------
The word in is a boolean operator that takes two strings and returns
True if the first appears as a substring in the second:
::
>>> 'a' in 'banana'
True
>>> 'seed' in 'banana'
False
For example, the following function prints all the letters from word1
that also appear in word2:
::
def in_both(word1, word2):
for letter in word1:
if letter in word2:
print(letter)
With well-chosen variable names, Python sometimes reads like English.
You could read this loop, “for (each) letter in (the first) word, if
(the) letter (appears) in (the second) word, print (the) letter.”
Here’s what you get if you compare apples and oranges:
::
>>> in_both('apples', 'oranges')
a
e
s
String comparison
-----------------
The relational operators work on strings. To see if two strings are
equal:
::
if word == 'banana':
print('All right, bananas.')
Other relational operations are useful for putting words in alphabetical
order:
::
if word < 'banana':
print('Your word, ' + word + ', comes before banana.')
elif word > 'banana':
print('Your word, ' + word + ', comes after banana.')
else:
print('All right, bananas.')
Python does not handle uppercase and lowercase letters the same way
people do. All the uppercase letters come before all the lowercase
letters, so:
::
Your word, Pineapple, comes before banana.
A common way to address this problem is to convert strings to a standard
format, such as all lowercase, before performing the comparison. Keep
that in mind in case you have to defend yourself against a man armed
with a Pineapple.
Debugging
---------
When you use indices to traverse the values in a sequence, it is tricky
to get the beginning and end of the traversal right. Here is a function
that is supposed to compare two words and return True if one of the
words is the reverse of the other, but it contains two errors:
::
def is_reverse(word1, word2):
if len(word1) != len(word2):
return False
i = 0
j = len(word2)
while j > 0:
if word1[i] != word2[j]:
return False
i = i+1
j = j-1
return True
The first if statement checks whether the words are the same length. If
not, we can return False immediately. Otherwise, for the rest of the
function, we can assume that the words are the same length. This is an
example of the guardian pattern in Section [guardian].
i and j are indices: i traverses word1 forward while j traverses word2
backward. If we find two letters that don’t match, we can return False
immediately. If we get through the whole loop and all the letters match,
we return True.
If we test this function with the words “pots” and “stop”, we expect the
return value True, but we get an IndexError:
::
>>> is_reverse('pots', 'stop')
...
File "reverse.py", line 15, in is_reverse
if word1[i] != word2[j]:
IndexError: string index out of range
For debugging this kind of error, my first move is to print the values
of the indices immediately before the line where the error appears.
::
while j > 0:
print(i, j) # print here
if word1[i] != word2[j]:
return False
i = i+1
j = j-1
Now when I run the program again, I get more information:
::
>>> is_reverse('pots', 'stop')
0 4
...
IndexError: string index out of range
The first time through the loop, the value of j is 4, which is out of
range for the string ``'pots'``. The index of the last character is 3,
so the initial value for j should be len(word2)-1.
If I fix that error and run the program again, I get:
::
>>> is_reverse('pots', 'stop')
0 3
1 2
2 1
True
This time we get the right answer, but it looks like the loop only ran
three times, which is suspicious. To get a better idea of what is
happening, it is useful to draw a state diagram. During the first
iteration, the frame for ``is_reverse`` is shown in Figure [fig.state4].
.. figure:: figs/state4.pdf
:alt: State diagram.
State diagram.
I took some license by arranging the variables in the frame and adding
dotted lines to show that the values of i and j indicate characters in
word1 and word2.
Starting with this diagram, run the program on paper, changing the
values of i and j during each iteration. Find and fix the second error
in this function. [isreverse]
.. _glossary08:
Glossary
--------
.. include:: glossary/08.txt
Exercises
---------
Read the documentation of the string methods at
http://docs.python.org/3/library/stdtypes.html#string-methods. You might
want to experiment with some of them to make sure you understand how
they work. strip and replace are particularly useful.
The documentation uses a syntax that might be confusing. For example, in
``find(sub[, start[, end]])``, the brackets indicate optional arguments.
So sub is required, but start is optional, and if you include start,
then end is optional.
There is a string method called count that is similar to the function in
Section [counter]. Read the documentation of this method and write an
invocation that counts the number of a’s in ``'banana'``.
A string slice can take a third index that specifies the “step size”;
that is, the number of spaces between successive characters. A step size
of 2 means every other character; 3 means every third, etc.
::
>>> fruit = 'banana'
>>> fruit[0:5:2]
'bnn'
A step size of -1 goes through the word backwards, so the slice
``[::-1]`` generates a reversed string.
Use this idiom to write a one-line version of ``is_palindrome`` from
Exercise [palindrome].
The following functions are all *intended* to check whether a string
contains any lowercase letters, but at least some of them are wrong. For
each function, describe what the function actually does (assuming that
the parameter is a string).
::
def any_lowercase1(s):
for c in s:
if c.islower():
return True
else:
return False
def any_lowercase2(s):
for c in s:
if 'c'.islower():
return 'True'
else:
return 'False'
def any_lowercase3(s):
for c in s:
flag = c.islower()
return flag
def any_lowercase4(s):
flag = False
for c in s:
flag = flag or c.islower()
return flag
def any_lowercase5(s):
for c in s:
if not c.islower():
return False
return True
[exrotate] A Caesar cypher is a weak form of encryption that involves
“rotating” each letter by a fixed number of places. To rotate a letter
means to shift it through the alphabet, wrapping around to the beginning
if necessary, so ’A’ rotated by 3 is ’D’ and ’Z’ rotated by 1 is ’A’.
To rotate a word, rotate each letter by the same amount. For example,
“cheer” rotated by 7 is “jolly” and “melon” rotated by -10 is “cubed”.
In the movie *2001: A Space Odyssey*, the ship computer is called HAL,
which is IBM rotated by -1.
Write a function called ``rotate_word`` that takes a string and an
integer as parameters, and returns a new string that contains the
letters from the original string rotated by the given amount.
You might want to use the built-in function ord, which converts a
character to a numeric code, and chr, which converts numeric codes to
characters. Letters of the alphabet are encoded in alphabetical order,
so for example:
::
>>> ord('c') - ord('a')
2
Because ``'c'`` is the two-eth letter of the alphabet. But beware: the
numeric codes for upper case letters are different.
Potentially offensive jokes on the Internet are sometimes encoded in
ROT13, which is a Caesar cypher with rotation 13. If you are not easily
offended, find and decode some of them. Solution:
http://thinkpython2.com/code/rotate.py.