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LISFT0123 Pedro Leal - First Lab #13

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LISFT0123 Pedro Leal - First Lab #13

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49 changes: 49 additions & 0 deletions index.js
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Original file line number Diff line number Diff line change
@@ -1,7 +1,56 @@
// Iteration 1: Names and Input
console.log("I`m ready");

let hacker1 = "The driver's name is Leal";
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@lzaquine lzaquine Jan 17, 2023

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Here, instead of passing the variable as the whole string, you could've given just your name and console.log the string after, like:

const hacker1 = 'Leal';
 console.log(`The driver's name is ${hacker1}.`);
 const hacker2 = 'Duarte';
 console.log(`The navigator's name is ${hacker2}.`)

let hacker2 = "The navigator's name is Duarte";

// Iteration 2: Conditionals

let driverName = hacker1.slice(21);
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@lzaquine lzaquine Jan 17, 2023

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So here you wouldn't need to use slice();

let navigatorName = hacker2.slice(24);



let numOfCharDriver = driverName.length;
let numOfCharNavigator = navigatorName.length;


if( driverName.length > navigatorName.length){
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@lzaquine lzaquine Jan 17, 2023

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Great job on creating the variables numOfCharDriver and numOfCharNavigator . Here on the if statement, you could've used them like:

if( numOfCharDriver > numOfCharNavigator)

console.log("The driver has the longest name, it has " + numOfCharDriver + " characters");
}
if(driverName.length < navigatorName.length){
console.log("It seems that the navigator has the longest name, it has "+ numOfCharNavigator + " characters.");
}
else {
console.log("Wow, you both have equally long names, " + numOfCharDriver + " characters!");
}


// Iteration 3: Loops

//3.1
for (let i = 0; i < driverName.length; i++) {
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@lzaquine lzaquine Jan 17, 2023

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Here, the idea was to print all the characters of the driver's name, separated by a space and in capitals i.e. "L E A L".

A good solution would be:

let withSpace = '';
for (let i = 0; i < hacker1.length; i++) {
     withSpace += hacker1.[i] + ' ';
 }
console.log(withSpace.toUpperCase());

console.log(driverName.toUpperCase()[i]);
console.log(driverName.toUpperCase()[0]+ " " + driverName.toUpperCase()[1] + " " + driverName.toUpperCase()[2] + " " + driverName.toUpperCase()[3]);
}

//3.2

for(let i = navigatorName.length -1 ; i >= 0; i--){
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@lzaquine lzaquine Jan 17, 2023

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Here, the idea was to print all the characters of the navigator's name in reverse order. i.e. "etrauD"

One way of doing that:

let reverseName = '';
for (let i = hacker2.length - 1; i >= 0; i--) {
  reverseName += hacker2[i];
}
console.log(reverseName);

console.log(navigatorName[i]);
}

//3.3

if (hacker1 > hacker2) {

console.log (`The driver's name goes first.`)

} else if (hacker1 < hacker2) {

console.log (`Yo, the navigator goes first definitely.`)

} else {

console.log (`What?! You both have the same name?`)
}