def isValid(s):

# Step 1: Count the frequency of each character

char_count = {}

for char in s:

char_count[char] = char_count.get(char, 0) + 1

# Step 2: Identify the frequencies of each unique character

frequencies = list(char_count.values())

# Step 3: Check if the frequencies satisfy the conditions

unique_frequencies = set(frequencies)

if len(unique_frequencies) == 1:

# All characters have the same frequency

return "YES"

elif len(unique_frequencies) == 2:

# Two unique frequencies are possible

freq1, freq2 = unique_frequencies

count1 = frequencies.count(freq1)

count2 = frequencies.count(freq2)

# Check if removing one character can make the string valid

if (count1 == 1 and (freq1 == 1 or freq1 - 1 == freq2)) or (count2 == 1 and (freq2 == 1 or freq2 - 1 == freq1)):

return "YES"

# If none of the conditions are met, the string is not valid

return "NO"

# Example usage:

s1 = "aabbcc"

s2 = "aabbccc"

s3 = "aabbcccc"

print(isValid(s1)) # Output: "YES"

print(isValid(s2)) # Output: "YES"

print(isValid(s3)) # Output: "NO"