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SUmOg2Integers.java
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90 lines (68 loc) · 2.45 KB
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package Math;
import java.util.Arrays;
/**
* Created by devpriyadave on 4/7/18.
*
* Calculate the sum of two integers a and b, but you are not allowed to use the operator + and -.
Example:
Given a = 1 and b = 2, return 3.
Idea is to get the bits and do if else
*/
public class SUmOg2Integers {
public int getSum(int a, int b) {
char[] bitA = Integer.toBinaryString(a).toCharArray();
char[] bitB = Integer.toBinaryString(b).toCharArray();
int ansLen = bitA.length > bitB.length ? bitA.length+1 : bitB.length + 1;
char[] bitAns = new char[ansLen];
char carry = '0';
int k = bitAns.length -1;
for(int i = bitA.length - 1, j= bitB.length - 1; k >=0 ;i--, j -- , k--) {
if(i >=0 && j >=0) {
if (bitA[i] == '1' && bitB[j] == '1' && carry == '1') {
bitAns[k] = '1';
carry = '1';
} else if (bitA[i] == '1' && bitB[j] == '1') {
bitAns[k] = '0';
carry = '1';
} else if (bitA[i] == '1' && bitB[j] == '0' && carry == '1') {
bitAns[k] = '0';
carry = '1';
} else if (bitA[i] == '0' && bitB[j] == '1' && carry == '1') {
bitAns[k] = '0';
carry = '1';
} else {
bitAns[k] = '1';
carry = '0';
}
} else if(i>=0) {
if (bitA[i] == '1' && carry == '1') {
bitAns[k] = '1';
carry = '0';
} else if (bitA[i] == '0' && carry == '1') {
bitAns[k] = '1';
carry = '0';
} else {
bitAns[k] = bitA[i];
}
} else if(j>=0) {
if (bitB[j] == '1' && carry == '1') {
bitAns[k] = '1';
carry = '0';
} else if (bitB[i] == '0' && carry == '1') {
bitAns[k] = '1';
carry = '0';
} else {
bitAns[k] = bitB[i];
}
} else {
if (carry == '1') {
bitAns[k] = '1';
carry = '0';
} else {
bitAns[k] = '0';
};
}
}
return Integer.parseInt(Arrays.toString(bitAns));
}
}