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zigzag-conversion.cpp
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73 lines (54 loc) · 1.45 KB
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/*
The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
P A H N
A P L S I I G
Y I R
And then read line by line: "PAHNAPLSIIGYIR"
Write the code that will take a string and make this conversion given a number of rows:
string convert(string s, int numRows);
Example 1:
Input: s = "PAYPALISHIRING", numRows = 3
Output: "PAHNAPLSIIGYIR"
Example 2:
Input: s = "PAYPALISHIRING", numRows = 4
Output: "PINALSIGYAHRPI"
Explanation:
P I N
A L S I G
Y A H R
P I
*/
#include <iostream>
#include <string>
#include <vector>
class Solution {
public:
std::string convert(std::string s, int numRows) {
if(numRows <= 1) return s;
std::vector<std::string> vec(numRows); // if array is used memory usage will be low
bool flag = true;
int y = 0;
for(int i=0; i<s.size(); i++)
{
vec[y] += s[i];
if(y==0) flag = true;
else if(y==(numRows-1)) flag = false;
if(flag) y++;
else y--;
}
std::string ret;
for(int i=0; i<numRows; i++)
{
ret += vec[i];
}
return ret;
}
};
int main()
{
Solution s;
std::string str = "PAYPALISHIRING";
std::string result = s.convert(str,4);
std::cout<<result<<'\n';
return 0;
}