1832 United States presidential election in Missouri
Appearance
November 2 – December 5, 1832
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County Results
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| Elections in Missouri |
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The 1832 United States presidential election in Missouri took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
Missouri voted for the Democratic Party candidate, Andrew Jackson, over the National Republican candidate, Henry Clay. Jackson won Missouri by a margin of 30.33%. It is frequently reported that Jackson's popular vote win was unanimous, having received 5,159 or 5,192 votes. However, this was likely a reference to Jackson's plurality over Clay that was confounded with his total vote.[1]
Results
[edit]| 1832 United States presidential election in Missouri[2] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic | Andrew Jackson (incumbent) | 8,904 | 65.16% | 4 | |
| National Republican | Henry Clay | 4,760 | 34.84% | 0 | |
| Totals | 13,664 | 100.0% | 4 | ||
See also
[edit]References
[edit]- ^ Dubin, Michael J. United States Presidential Elections. 1788–1870: The Official Results by County and State. ISBN 978-0-7864-6422-7.
- ^ "Missouri Politics". Jeffersonian Republican. September 21, 1833. p. 2.