Mercurial > p > roundup > code
view scripts/stats.xmlrpc.py @ 6757:f6dd6cd920bc
Split edit ok and edit not ok test into two tests.
Having them combined seems to cause them to fail in CI.
Will splitting them with separate setup for each work better?
| author | John Rouillard <rouilj@ieee.org> |
|---|---|
| date | Tue, 05 Jul 2022 02:02:38 -0400 |
| parents | 75da037d1c54 |
| children |
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"""Count how many issues use each bpo field and print a report.""" """ sample output: https://github.com/psf/gh-migration/issues/5#issuecomment-935697646""" import xmlrpc.client from collections import defaultdict class SpecialTransport(xmlrpc.client.SafeTransport): def send_content(self, connection, request_body): connection.putheader("Referer", "https://bugs.python.org/") connection.putheader("Origin", "https://bugs.python.org") connection.putheader("X-Requested-With", "XMLHttpRequest") xmlrpc.client.SafeTransport.send_content(self, connection, request_body) # connect to bpo roundup = xmlrpc.client.ServerProxy('https://bugs.python.org/xmlrpc', transport=SpecialTransport(), allow_none=True) # map bpo classes -> propname # the class is the name of the class (e.g. issue_type, keyword -- # also used in e.g. in https://bugs.python.org/keyword) # the propname is the name used as attribute on the issue class # (e.g. issue.type, issue.keywords) classes = { # 'status': 'status', # skip this 'issue_type': 'type', 'stage': 'stage', 'component': 'components', 'version': 'versions', 'resolution': 'resolution', 'priority': 'priority', 'keyword': 'keywords', } # find the id for the 'open' status open_id = roundup.lookup('status', 'open') print(f'* Counting total issues...') total_issues_num = len(roundup.filter('issue', None, {})) print(f'* Counting open issues...') # use this list to filter only the open issues open_issues = roundup.filter('issue', None, {'status': open_id}) open_issues_num = len(open_issues) # save the totals in a dict with this structure: # totals[propname][open/all][num/perc][name] # where propname is e.g. 'keyword' and name is e.g. 'easy' totals = defaultdict(lambda: {'all': {'perc': {}, 'num': {}}, 'open': {'perc': {}, 'num': {}}}) for cls, propname in classes.items(): print(f'* Counting <{cls}>...') # get the list of ids/names for the given class (e.g. 'easy' is 6) ids = roundup.list(cls, 'id') names = roundup.list(cls, 'name') for id, name in zip(ids, names): # filter and count on *all* issues with the given propname tot_all = len(roundup.filter('issue', None, {propname: id})) totals[propname]['all']['num'][name] = tot_all totals[propname]['all']['perc'][name] = tot_all / total_issues_num # filter and count on *open* issues with the given propname tot_open = len(roundup.filter('issue', open_issues, {propname: id})) totals[propname]['open']['num'][name] = tot_open totals[propname]['open']['perc'][name] = tot_open / open_issues_num print(f'Issues (open/all): {open_issues_num}/{total_issues_num}') # print a list of markdown tables for each bpo class name for propname in classes.values(): print(f'### {propname}') print('| bpo field | open | all |') print('| :--- | ---: | ---: |') # pick the dict for the given propname (e.g. keywords) proptots = totals[propname] names = proptots['open']['num'] # sort the names (e.g. 'easy') in reverse order # based on the number of open issues for name in sorted(names, key=names.get, reverse=True): # get and print num/perc for all/open issues issues_all = proptots['all']['num'][name] issues_open = proptots['open']['num'][name] perc_all = proptots['all']['perc'][name] perc_open = proptots['open']['perc'][name] print(f'| {name:20} | {issues_open:>5} ({perc_open:5.1%}) |' f' {issues_all:>5} ({perc_all:5.1%}) |') # calc and print num/perc for all/open issues tot_issues_all = sum(proptots['all']['num'].values()) tot_issues_open = sum(proptots['open']['num'].values()) tot_perc_all = sum(proptots['all']['perc'].values()) tot_perc_open = sum(proptots['open']['perc'].values()) print(f'| **Total** | {tot_issues_open:>5} ({tot_perc_open:5.1%}) |' f' {tot_issues_all:>5} ({tot_perc_all:5.1%}) |')
