Mercurial > p > roundup > code
view roundup/token.py @ 6757:f6dd6cd920bc
Split edit ok and edit not ok test into two tests.
Having them combined seems to cause them to fail in CI.
Will splitting them with separate setup for each work better?
| author | John Rouillard <rouilj@ieee.org> |
|---|---|
| date | Tue, 05 Jul 2022 02:02:38 -0400 |
| parents | f023edbeb24d |
| children |
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# # Copyright (c) 2001 Richard Jones, richard@bofh.asn.au. # This module is free software, and you may redistribute it and/or modify # under the same terms as Python, so long as this copyright message and # disclaimer are retained in their original form. # # This module is distributed in the hope that it will be useful, # but WITHOUT ANY WARRANTY; without even the implied warranty of # MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. # """This module provides the tokeniser used by roundup-admin. """ __docformat__ = 'restructuredtext' def token_split(s, whitespace=' \r\n\t', quotes='\'"', escaped={'r': '\r', 'n': '\n', 't': '\t'}): r'''Split the string up into tokens. An occurence of a ``'`` or ``"`` in the input will cause the splitter to ignore whitespace until a matching quote char is found. Embedded non-matching quote chars are also skipped. Whitespace and quoting characters may be escaped using a backslash. ``\r``, ``\n`` and ``\t`` are converted to carriage-return, newline and tab. All other backslashed characters are left as-is. Valid examples:: hello world (2 tokens: hello, world) "hello world" (1 token: hello world) "Roch'e" Compaan (2 tokens: Roch'e Compaan) Roch\'e Compaan (2 tokens: Roch'e Compaan) address="1 2 3" (1 token: address=1 2 3) \\ (1 token: \) \n (1 token: a newline) \o (1 token: \o) Invalid examples:: "hello world (no matching quote) Roch'e Compaan (no matching quote) ''' l = [] pos = 0 NEWTOKEN = 'newtoken' TOKEN = 'token' QUOTE = 'quote' ESCAPE = 'escape' quotechar = '' state = NEWTOKEN oldstate = '' # one-level state stack ;) length = len(s) token = '' while 1: # end of string, finish off the current token if pos == length: if state == QUOTE: raise ValueError elif state == TOKEN: l.append(token) break c = s[pos] if state == NEWTOKEN: # looking for a new token if c in quotes: # quoted token state = QUOTE quotechar = c pos = pos + 1 continue elif c in whitespace: # skip whitespace pos = pos + 1 continue elif c == '\\': pos = pos + 1 oldstate = TOKEN state = ESCAPE continue # otherwise we have a token state = TOKEN elif state == TOKEN: if c in whitespace: # have a token, and have just found a whitespace terminator l.append(token) pos = pos + 1 state = NEWTOKEN token = '' continue elif c in quotes: # have a token, just found embedded quotes state = QUOTE quotechar = c pos = pos + 1 continue elif c == '\\': pos = pos + 1 oldstate = state state = ESCAPE continue elif state == QUOTE and c == quotechar: # in a quoted token and found a matching quote char pos = pos + 1 # now we're looking for whitespace state = TOKEN continue elif state == ESCAPE: # escaped-char conversions (t, r, n) # TODO: octal, hexdigit state = oldstate if c in escaped: c = escaped[c] # just add this char to the token and move along token = token + c pos = pos + 1 return l # vim: set filetype=python ts=4 sw=4 et si
