view roundup/support.py @ 3696:790363e96852

Sorting/grouping by multiple properties. - Implement sorting/grouping by multiple properties for the web interface. I'm now using @sort0/@sortdir0,@sort1/@sortdir1,... and @group0/@groupdir0,... when generating URLs from a search template. These are converted to a list internally. When saving URLs (e.g. when storing queries) I'm using @sort=prop1,prop2,... and @group=... with optional '-' prepended to individual props. This means saved URLs are backward compatible with existing trackers (and yes, this was a design goal). I need the clumsy version with @sort0,@sort1 etc, because I'm currently using several selectors and checkboxes (as the classic template does, too). I don't think there is a way around that in HTML? - Updated (hopefully all) documentation to reflect the new URL format and the consequences in the web-interface. - I've set the number of sort/group properties in the classic template to two -- this can easily be reverted by changing n_sort to 1. Richard, would you look over these changes? I've set a tag before and (will set) after commit, so that it would be easy to merge out. Don't be too scared about the size of the change, most is documentation, the guts are in cgi/templating.py and small changes in the classic template.
author Ralf Schlatterbeck <schlatterbeck@users.sourceforge.net>
date Wed, 30 Aug 2006 20:28:26 +0000
parents 193f316dbbe9
children 0a05c4d9a221
line wrap: on
line source

"""Implements various support classes and functions used in a number of
places in Roundup code.
"""

__docformat__ = 'restructuredtext'

import os, time, sys, re

class TruthDict:
    '''Returns True for valid keys, False for others.
    '''
    def __init__(self, keys):
        if keys:
            self.keys = {}
            for col in keys:
                self.keys[col] = 1
        else:
            self.__getitem__ = lambda name: 1

    def __getitem__(self, name):
        return self.keys.has_key(name)

def ensureParentsExist(dest):
    if not os.path.exists(os.path.dirname(dest)):
        os.makedirs(os.path.dirname(dest))

class PrioList:
    '''Manages a sorted list.

    Currently only implements method 'append' and iteration from a
    full list interface.
    Implementation: We manage a "sorted" status and sort on demand.
    Appending to the list will require re-sorting before use.
    >>> p = PrioList()
    >>> for i in 5,7,1,-1:
    ...  p.append(i)
    ...
    >>> for k in p:
    ...  print k
    ...
    -1
    1
    5
    7

    '''
    def __init__(self):
        self.list   = []
        self.sorted = True

    def append(self, item):
        self.list.append(item)
        self.sorted = False

    def __iter__(self):
        if not self.sorted:
            self.list.sort()
            self.sorted = True
        return iter(self.list)

class Progress:
    '''Progress display for console applications.

    See __main__ block at end of file for sample usage.
    '''
    def __init__(self, info, sequence):
        self.info = info
        self.sequence = iter(sequence)
        self.total = len(sequence)
        self.start = self.now = time.time()
        self.num = 0
        self.stepsize = self.total / 100 or 1
        self.steptimes = []
        self.display()

    def __iter__(self): return self

    def next(self):
        self.num += 1

        if self.num > self.total:
            print self.info, 'done', ' '*(75-len(self.info)-6)
            sys.stdout.flush()
            return self.sequence.next()

        if self.num % self.stepsize:
            return self.sequence.next()

        self.display()
        return self.sequence.next()

    def display(self):
        # figure how long we've spent - guess how long to go
        now = time.time()
        steptime = now - self.now
        self.steptimes.insert(0, steptime)
        if len(self.steptimes) > 5:
            self.steptimes.pop()
        steptime = sum(self.steptimes) / len(self.steptimes)
        self.now = now
        eta = steptime * ((self.total - self.num)/self.stepsize)

        # tell it like it is (or might be)
        if now - self.start > 3:
            M = eta / 60
            H = M / 60
            M = M % 60
            S = eta % 60
            if self.total:
                s = '%s %2d%% (ETA %02d:%02d:%02d)'%(self.info,
                    self.num * 100. / self.total, H, M, S)
            else:
                s = '%s 0%% (ETA %02d:%02d:%02d)'%(self.info, H, M, S)
        elif self.total:
            s = '%s %2d%%'%(self.info, self.num * 100. / self.total)
        else:
            s = '%s %d done'%(self.info, self.num)
        sys.stdout.write(s + ' '*(75-len(s)) + '\r')
        sys.stdout.flush()

LEFT = 'left'
LEFTN = 'left no strip'
RIGHT = 'right'
CENTER = 'center'

def align(line, width=70, alignment=LEFTN):
    ''' Code from http://www.faqts.com/knowledge_base/view.phtml/aid/4476 '''
    if alignment == CENTER:
        line = line.strip()
        space = width - len(line)
        return ' '*(space/2) + line + ' '*(space/2 + space%2)
    elif alignment == RIGHT:
        line = line.rstrip()
        space = width - len(line)
        return ' '*space + line
    else:
        if alignment == LEFT:
            line = line.lstrip()
        space = width - len(line)
        return line + ' '*space


def format_line(columns, positions, contents, spacer=' | ',
        collapse_whitespace=True, wsre=re.compile(r'\s+')):
    ''' Fill up a single row with data from the contents '''
    l = []
    data = 0
    for i in range(len(columns)):
        width, alignment = columns[i]
        content = contents[i]
        col = ''
        while positions[i] < len(content):
            word = content[positions[i]]
            # if we hit a newline, honor it
            if '\n' in word:
                # chomp
                positions[i] += 1
                break

            # make sure this word fits
            if col and len(word) + len(col) > width:
                break

            # no whitespace at start-of-line
            if collapse_whitespace and wsre.match(word) and not col:
                # chomp
                positions[i] += 1
                continue

            col += word
            # chomp
            positions[i] += 1
        if col:
            data = 1
        col = align(col, width, alignment)
        l.append(col)

    if not data:
        return ''
    return spacer.join(l).rstrip()


def format_columns(columns, contents, spacer=' | ', collapse_whitespace=True,
        splitre=re.compile(r'(\n|\r\n|\r|[ \t]+|\S+)')):
    ''' Format the contents into columns, with 'spacing' between the
        columns
    '''
    assert len(columns) == len(contents), \
        'columns and contents must be same length'

    # split the text into words, spaces/tabs and newlines
    for i in range(len(contents)):
        contents[i] = splitre.findall(contents[i])

    # now process line by line
    l = []
    positions = [0]*len(contents)
    while 1:
        l.append(format_line(columns, positions, contents, spacer,
            collapse_whitespace))

        # are we done?
        for i in range(len(contents)):
            if positions[i] < len(contents[i]):
                break
        else:
            break
    return '\n'.join(l)

def wrap(text, width=75, alignment=LEFTN):
    return format_columns(((width, alignment),), [text],
        collapse_whitespace=False)

# Python2.3 backwards-compatibility-hack. Should be removed (and clients
# fixed to use built-in reversed/sorted) when we abandon support for
# python2.3
try:
    reversed = reversed
except NameError:
    def reversed(x):
        x = list(x)
        x.reverse()
        return x

try:
    sorted = sorted
except NameError:
    def sorted(iter, cmp=None, key=None, reverse=False):
        if key:
            l = []
            cnt = 0 # cnt preserves original sort-order
            inc = [1, -1][bool(reverse)] # count down on reverse
            for x in iter:
                l.append ((key(x), cnt, x))
                cnt += inc
        else:
            l = list(iter)
        if cmp:
            l.sort(cmp = cmp)
        else:
            l.sort()
        if reverse:
            l.reverse()
        if key:
            return [x[-1] for x in l]
        return l

# vim: set et sts=4 sw=4 :

Roundup Issue Tracker: http://roundup-tracker.org/