view scripts/stats.xmlrpc.py @ 7800:2d4684e4702d

fix: enhancement to history command output and % template fix. Rather than using the key field, use the label field for descriptions. Call cls.labelprop(default_to_id=True) so it returns id rather than the first sorted property name. If labelprop() returns 'id' or 'title', we return nothing. 'id' means there is no label set and no properties named 'name' or 'title'. So have the caller do whatever it wants (prepend classname for example) when there is no human readable name. This prevents %(name)s%(key)s from producing: 23(23). Also don't accept the 'title' property. Titles can be too long. Arguably we could: '%(name)20s' to limit the title length. However without ellipses or something truncating the title might be confusing. So again pretend there is no human readable name.
author John Rouillard <rouilj@ieee.org>
date Tue, 12 Mar 2024 11:52:17 -0400
parents 75da037d1c54
children
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"""Count how many issues use each bpo field and print a report."""
""" sample output: https://github.com/psf/gh-migration/issues/5#issuecomment-935697646"""

import xmlrpc.client

from collections import defaultdict

class SpecialTransport(xmlrpc.client.SafeTransport):
    def send_content(self, connection, request_body):
        connection.putheader("Referer", "https://bugs.python.org/")
        connection.putheader("Origin", "https://bugs.python.org")
        connection.putheader("X-Requested-With", "XMLHttpRequest")
        xmlrpc.client.SafeTransport.send_content(self, connection, request_body)

# connect to bpo
roundup = xmlrpc.client.ServerProxy('https://bugs.python.org/xmlrpc',
                                    transport=SpecialTransport(),
                                    allow_none=True)

# map bpo classes -> propname
# the class is the name of the class (e.g. issue_type, keyword --
# also used in e.g. in https://bugs.python.org/keyword)
# the propname is the name used as attribute on the issue class
# (e.g. issue.type, issue.keywords)
classes = {
    # 'status': 'status',  # skip this
    'issue_type': 'type',
    'stage': 'stage',
    'component': 'components',
    'version': 'versions',
    'resolution': 'resolution',
    'priority': 'priority',
    'keyword': 'keywords',
}

# find the id for the 'open' status
open_id = roundup.lookup('status', 'open')

print(f'* Counting total issues...')
total_issues_num = len(roundup.filter('issue', None, {}))

print(f'* Counting open issues...')
# use this list to filter only the open issues
open_issues = roundup.filter('issue', None, {'status': open_id})
open_issues_num = len(open_issues)

# save the totals in a dict with this structure:
#   totals[propname][open/all][num/perc][name]
# where propname is e.g. 'keyword' and name is e.g. 'easy'
totals = defaultdict(lambda: {'all': {'perc': {}, 'num': {}},
                              'open': {'perc': {}, 'num': {}}})
for cls, propname in classes.items():
    print(f'* Counting <{cls}>...')
    # get the list of ids/names for the given class (e.g. 'easy' is 6)
    ids = roundup.list(cls, 'id')
    names = roundup.list(cls, 'name')
    for id, name in zip(ids, names):
        # filter and count on *all* issues with the given propname
        tot_all = len(roundup.filter('issue', None, {propname: id}))
        totals[propname]['all']['num'][name] = tot_all
        totals[propname]['all']['perc'][name] = tot_all / total_issues_num
        # filter and count on *open* issues with the given propname
        tot_open = len(roundup.filter('issue', open_issues, {propname: id}))
        totals[propname]['open']['num'][name] = tot_open
        totals[propname]['open']['perc'][name] = tot_open / open_issues_num


print(f'Issues (open/all): {open_issues_num}/{total_issues_num}')

# print a list of markdown tables for each bpo class name
for propname in classes.values():
    print(f'### {propname}')
    print('| bpo field | open | all |')
    print('| :--- | ---: | ---: |')
    # pick the dict for the given propname (e.g. keywords)
    proptots = totals[propname]
    names = proptots['open']['num']
    # sort the names (e.g. 'easy') in reverse order
    # based on the number of open issues
    for name in sorted(names, key=names.get, reverse=True):
        # get and print num/perc for all/open issues
        issues_all = proptots['all']['num'][name]
        issues_open = proptots['open']['num'][name]
        perc_all = proptots['all']['perc'][name]
        perc_open = proptots['open']['perc'][name]
        print(f'| {name:20} | {issues_open:>5} ({perc_open:5.1%}) |'
              f' {issues_all:>5} ({perc_all:5.1%}) |')
    # calc and print num/perc for all/open issues
    tot_issues_all = sum(proptots['all']['num'].values())
    tot_issues_open = sum(proptots['open']['num'].values())
    tot_perc_all = sum(proptots['all']['perc'].values())
    tot_perc_open = sum(proptots['open']['perc'].values())
    print(f'| **Total**            | {tot_issues_open:>5} ({tot_perc_open:5.1%}) |'
            f' {tot_issues_all:>5} ({tot_perc_all:5.1%}) |')


Roundup Issue Tracker: http://roundup-tracker.org/