view roundup/token.py @ 6565:2c2dbfc332ba

Try to handle multiple connections better. The session database is a hot spot. When multiple requests (e.g. 20) come in at the same time session database contention can get great. The original code didn't retry session database access when the open failed. This resulted in errors at the client. The second pass delayed 0.01 seconds and retried. It was better but we still had multiple second stalls. I think the first request got in, everybody else backed up and then retried at the same time. Again they stepped on each other. With logging I would see many counters go all the way to low single digits or to -1 indicating falure. This pass uses randomint to generate delays from 0-.125 seconds in 5ms increments. This performs better in testing. I rarely saw a counter less than 13 (2 failed retries). Current logging starts after 6 failures and counts down until success or failure.
author John Rouillard <rouilj@ieee.org>
date Thu, 16 Dec 2021 20:02:00 -0500
parents f023edbeb24d
children
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#
# Copyright (c) 2001 Richard Jones, richard@bofh.asn.au.
# This module is free software, and you may redistribute it and/or modify
# under the same terms as Python, so long as this copyright message and
# disclaimer are retained in their original form.
#
# This module is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.
#

"""This module provides the tokeniser used by roundup-admin.
"""
__docformat__ = 'restructuredtext'


def token_split(s, whitespace=' \r\n\t', quotes='\'"',
                escaped={'r': '\r', 'n': '\n', 't': '\t'}):
    r'''Split the string up into tokens. An occurence of a ``'`` or ``"`` in
    the input will cause the splitter to ignore whitespace until a matching
    quote char is found. Embedded non-matching quote chars are also skipped.

    Whitespace and quoting characters may be escaped using a backslash.
    ``\r``, ``\n`` and ``\t`` are converted to carriage-return, newline and
    tab.  All other backslashed characters are left as-is.

    Valid examples::

           hello world      (2 tokens: hello, world)
           "hello world"    (1 token: hello world)
           "Roch'e" Compaan (2 tokens: Roch'e Compaan)
           Roch\'e Compaan  (2 tokens: Roch'e Compaan)
           address="1 2 3"  (1 token: address=1 2 3)
           \\               (1 token: \)
           \n               (1 token: a newline)
           \o               (1 token: \o)

    Invalid examples::

           "hello world     (no matching quote)
           Roch'e Compaan   (no matching quote)
    '''
    l = []
    pos = 0
    NEWTOKEN = 'newtoken'
    TOKEN = 'token'
    QUOTE = 'quote'
    ESCAPE = 'escape'
    quotechar = ''
    state = NEWTOKEN
    oldstate = ''    # one-level state stack ;)
    length = len(s)
    token = ''
    while 1:
        # end of string, finish off the current token
        if pos == length:
            if state == QUOTE: raise ValueError
            elif state == TOKEN: l.append(token)
            break
        c = s[pos]
        if state == NEWTOKEN:
            # looking for a new token
            if c in quotes:
                # quoted token
                state = QUOTE
                quotechar = c
                pos = pos + 1
                continue
            elif c in whitespace:
                # skip whitespace
                pos = pos + 1
                continue
            elif c == '\\':
                pos = pos + 1
                oldstate = TOKEN
                state = ESCAPE
                continue
            # otherwise we have a token
            state = TOKEN
        elif state == TOKEN:
            if c in whitespace:
                # have a token, and have just found a whitespace terminator
                l.append(token)
                pos = pos + 1
                state = NEWTOKEN
                token = ''
                continue
            elif c in quotes:
                # have a token, just found embedded quotes
                state = QUOTE
                quotechar = c
                pos = pos + 1
                continue
            elif c == '\\':
                pos = pos + 1
                oldstate = state
                state = ESCAPE
                continue
        elif state == QUOTE and c == quotechar:
            # in a quoted token and found a matching quote char
            pos = pos + 1
            # now we're looking for whitespace
            state = TOKEN
            continue
        elif state == ESCAPE:
            # escaped-char conversions (t, r, n)
            # TODO: octal, hexdigit
            state = oldstate
            if c in escaped:
                c = escaped[c]
        # just add this char to the token and move along
        token = token + c
        pos = pos + 1
    return l

# vim: set filetype=python ts=4 sw=4 et si

Roundup Issue Tracker: http://roundup-tracker.org/