Mercurial > p > roundup > code
view roundup/support.py @ 5132:0142b4fb5a2d
issue2550648 - partial fix for problem in this issue. Ezio Melotti
reported that the expression editor allowed the user to generate an
expression using retired values. To align the expression editor with
the simple dropdown search item, retired values are now removed from
the expression editor.
Do we really want this though? Supposed a keyword is retired and I
want to search for an issue with that retired keyword? Do we have a
best policy document that says to remove retired keywords from all
places it could possibly be used? It could be argued that the simple
search dropdown is wrong and should allow selecting retired values.
| author | John Rouillard <rouilj@ieee.org> |
|---|---|
| date | Fri, 08 Jul 2016 19:31:02 -0400 |
| parents | ac0c117cd24c |
| children | 64b05e24dbd8 |
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"""Implements various support classes and functions used in a number of places in Roundup code. """ __docformat__ = 'restructuredtext' import os, time, sys, re class TruthDict: '''Returns True for valid keys, False for others. ''' def __init__(self, keys): if keys: self.keys = {} for col in keys: self.keys[col] = 1 else: self.__getitem__ = lambda name: 1 def __getitem__(self, name): return self.keys.has_key(name) def ensureParentsExist(dest): if not os.path.exists(os.path.dirname(dest)): os.makedirs(os.path.dirname(dest)) class PrioList: '''Manages a sorted list. Currently only implements method 'append' and iteration from a full list interface. Implementation: We manage a "sorted" status and sort on demand. Appending to the list will require re-sorting before use. >>> p = PrioList() >>> for i in 5,7,1,-1: ... p.append(i) ... >>> for k in p: ... print k ... -1 1 5 7 ''' def __init__(self): self.list = [] self.sorted = True def append(self, item): self.list.append(item) self.sorted = False def __iter__(self): if not self.sorted: self.list.sort() self.sorted = True return iter(self.list) class Progress: '''Progress display for console applications. See __main__ block at end of file for sample usage. ''' def __init__(self, info, sequence): self.info = info self.sequence = iter(sequence) self.total = len(sequence) self.start = self.now = time.time() self.num = 0 self.stepsize = self.total / 100 or 1 self.steptimes = [] self.display() def __iter__(self): return self def next(self): self.num += 1 if self.num > self.total: print self.info, 'done', ' '*(75-len(self.info)-6) sys.stdout.flush() return self.sequence.next() if self.num % self.stepsize: return self.sequence.next() self.display() return self.sequence.next() def display(self): # figure how long we've spent - guess how long to go now = time.time() steptime = now - self.now self.steptimes.insert(0, steptime) if len(self.steptimes) > 5: self.steptimes.pop() steptime = sum(self.steptimes) / len(self.steptimes) self.now = now eta = steptime * ((self.total - self.num)/self.stepsize) # tell it like it is (or might be) if now - self.start > 3: M = eta / 60 H = M / 60 M = M % 60 S = eta % 60 if self.total: s = '%s %2d%% (ETA %02d:%02d:%02d)'%(self.info, self.num * 100. / self.total, H, M, S) else: s = '%s 0%% (ETA %02d:%02d:%02d)'%(self.info, H, M, S) elif self.total: s = '%s %2d%%'%(self.info, self.num * 100. / self.total) else: s = '%s %d done'%(self.info, self.num) sys.stdout.write(s + ' '*(75-len(s)) + '\r') sys.stdout.flush() # vim: set et sts=4 sw=4 :
